x^2/x+2-4/x+2

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Solution for x^2/x+2-4/x+2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(x^2)/x-(4/x)+2+2 = 0

(x^2)/x-4*x^-1+2+2 = 0

1*x^1-4*x^-1+4*x^0 = 0

(1*x^2+4*x^1-4*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^2+4*x^1-4*x^0) = 0

x^1

x^2+4*x-4 = 0

x^2+4*x-4 = 0

DELTA = 4^2-(-4*1*4)

DELTA = 32

DELTA > 0

x = (32^(1/2)-4)/(1*2) or x = (-32^(1/2)-4)/(1*2)

x = (4*2^(1/2)-4)/2 or x = (-4*2^(1/2)-4)/2

x in { (-4*2^(1/2)-4)/2, (4*2^(1/2)-4)/2} 

x in { (-4*2^(1/2)-4)/2, (4*2^(1/2)-4)/2 }

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